An ideal spring hangs from the ceiling. A 2.25 kg mass is hung from the spring, stretching the spring adistance d = 0.0875 m from its original length when it reaches equilibrium. The mass is then lifted up adistance L = 0.0275 m from the equilibrium position and released. What is the kinetic energy of the mass atthe instant it passes back through the equilibrium position?Numberequilibrium position

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Asked Dec 4, 2019
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An ideal spring hangs from the ceiling. A 2.25 kg mass is hung from the spring, stretching the spring a
distance d = 0.0875 m from its original length when it reaches equilibrium. The mass is then lifted up a
distance L = 0.0275 m from the equilibrium position and released. What is the kinetic energy of the mass at
the instant it passes back through the equilibrium position?
Number
equilibrium position
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An ideal spring hangs from the ceiling. A 2.25 kg mass is hung from the spring, stretching the spring a distance d = 0.0875 m from its original length when it reaches equilibrium. The mass is then lifted up a distance L = 0.0275 m from the equilibrium position and released. What is the kinetic energy of the mass at the instant it passes back through the equilibrium position? Number equilibrium position

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Step 1

The value of the spring constant is,

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mg kd (2.25)(9.8)-(0.0875) k 252 N/m

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Step 2

Therefore, the required k...

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1 KE mv 2 =-mm 2 т 1 2

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