An object has position given by the vector r = [3.0m + (6.0m/s)t] i + [2.0m - (2.0m/s2)t2] j, where quantities are in SI units. What is the speed of the object at t = 3.0s?
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An object has position given by the vector r = [3.0m + (6.0m/s)t] i + [2.0m - (2.0m/s2)t2] j, where quantities are in SI units. What is the speed of the object at t = 3.0s?
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- Figure OQ3.3 shows a birds-eye view of a car going around a highway curve. As the car moves from point 1 to point 2, its speed doubles. Which of the vectors (a) through (e) shows the direction of the cars average acceleration between these two points?A cart is propelled over an xy plane with acceleration components ax = 4.0 m/s2 and ay=-2.0 m/s2. Its initial velocity has components v0x = 8.0 m/s and v0y = 12 m/s. In unit-vector notation, what is the velocity of the cart when it reaches its greatest y coordinate?A particle starts from the origin of a three-dimensional coordinate system and undergoes two consecutive displacements: r1→=2.0miˆ+1.0mjˆ+3.0mkˆr2→=−1.0miˆ−3.0mjˆ−1.0mkˆr1→=2.0mi^+1.0mj^+3.0mk^r2→=−1.0mi^−3.0mj^−1.0mk^ What is the distance of the particle from the origin after these two displacements?
- Vectors A= 1.00i -2.00j and B=3.00i +4.00j what are the magnitude and direction of vector C=A+B ? what is the length of the path the object followed during the time interval from t=0.0s and t=9.0s?The velocity v→ of a particle moving in the xy plane is given by v→=(5.50t-5.00t2)î+9.00ĵ, with v→ in meters per second and t (> 0) in seconds. At t = 1.40 s and in unit-vector notation, At what positive time does the speed equal 10.0 m/s?Solving equations of motion Given an acceleration vector,initial velocity ⟨u0, v0, w0⟩, and initial position ⟨x0, y0, z0⟩, find thevelocity and position vectors, for t ≥ 0. a(t) = ⟨sin t, cos t, 1⟩, ⟨u0, v0, w0⟩ = ⟨0, 2, 0⟩,⟨x0, y0, z0⟩ = ⟨0, 0, 0⟩
- The position of a particle moving in an xy plane is given by = (1.00t3 − 3.00t) + (7.00 − 8.00t4) , with in meters and t in seconds. In unit-vector notation, calculate the following for t = 2.70 s.The velocity of a particle moving in the x-y plane is given by (6.98i + 6.68j) m/s at time t = 7.60 s. Its average acceleration during the next 0.014 s is (4.1i + 5.4j) m/s2. Determine the velocity v of the particle at t = 7.614 s and the angle θ between the average-acceleration vector and the velocity vector at t = 7.614 s.Answers:v = ( _____ i + _____ j) m/sθ = _____ °A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 î − 3.20 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (21.0 î − 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 ay = m/s2 (b) What is the direction of its acceleration with respect to unit vector î? ° counterclockwise from the +x-axis(c) If the fish maintains constant acceleration, where is it at t = 30.0 s? x = m y = m In what direction is it moving? ° counterclockwise from the +x-axis
- A fish swimming in a horizontal plane has velocity i = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 î − 3.20 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (21.0 î − 6.00 ĵ) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 ay = m/s2 (b) What is the direction of its acceleration with respect to unit vector î? ° counterclockwise from the +x-axis(c) If the fish maintains constant acceleration, where is it at t = 30.0 s? x = 542.5 Remember that you can treat the motions in the x and y directions separately. Each is then treated exactly as you would the one-dimensional case. m y = m In what direction is it moving? ° counterclockwise from the +x-axiThe position r→ of a particle moving in an xy plane is given by r→=(3.00t^3−7.00t)i^+(6.00−2.00t^4)j^ with r→ in meters and t in seconds. In unit-vector notation, calculate(a)r→, (b)v→, and (c)a→ for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the range of (-180o; 180o).If the vector components of the position of a particle moving in the xy plane as a function of time are x = (2.8 m/s2)t2 and y = (6.4 m/s3)t3, at what time t is the angle between the particle's velocity and the x axis equal to 45°?