An object is dropped from a tower, 1936 ft above the ground. The object's height above ground t seconds after the fall is s(t) = 1936 - 16t. Determine the velocity and acceleration of the object the moment it reaches the ground. The velocity of the object the moment it reaches the ground is ft/s. (Simplify your answer.)

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Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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An object is dropped from a tower, 1936 ft above the ground. The object's height above ground t seconds after the fall is s(t) = 1936 - 16t. Determine the velocity and
acceleration of the object the moment it reaches the ground.
The velocity of the object the moment it reaches the ground is ft/s.
(Simplify your answer.)
Enter your answer in the answer box and then click Check Answer.
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Transcribed Image Text:An object is dropped from a tower, 1936 ft above the ground. The object's height above ground t seconds after the fall is s(t) = 1936 - 16t. Determine the velocity and acceleration of the object the moment it reaches the ground. The velocity of the object the moment it reaches the ground is ft/s. (Simplify your answer.) Enter your answer in the answer box and then click Check Answer. Clear All Check Answer part remaining NIT
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