An object is dropped from a tower, 256 ft above the ground. The object's height above ground x seconds after the fall is s(x) 256-16x2. About how long does it takethe object to hit the ground? What is the object's velocity at the moment of impact?sec for the object to hit the groundIt takes(Round to the nearest tenth as needed.)ftThe object's velocity at the moment of impact issec

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Asked Oct 1, 2019
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An object is dropped from a tower, 256 ft above the ground. The object's height above ground x seconds after the fall is s(x) 256-16x2. About how long does it take
the object to hit the ground? What is the object's velocity at the moment of impact?
sec for the object to hit the ground
It takes
(Round to the nearest tenth as needed.)
ft
The object's velocity at the moment of impact is
sec
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An object is dropped from a tower, 256 ft above the ground. The object's height above ground x seconds after the fall is s(x) 256-16x2. About how long does it take the object to hit the ground? What is the object's velocity at the moment of impact? sec for the object to hit the ground It takes (Round to the nearest tenth as needed.) ft The object's velocity at the moment of impact is sec

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Expert Answer

Step 1

When it hits the ground then s(x)=0

We solve s(x)=0 for x....

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s(x) 256-16x2 0-256-16x2 16x2-256 256 x2= 16 x2 16 x=4

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