Question
Asked Oct 5, 2019
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If the initial time is t = 0 s and the final time is the final time shown on the graph, select whether each of the following are: up, down, or zero.

The average acceleration
The displacement
The average velocity

An object is hanging vertically on a rubber cord while oscillating up and down. In a coordinate system with the y axis pointing vertically up, the velocity of the object (in m/s) is shown below.
14
12
10
8
6
4
2
2
-4
-6
-8
-10
-12
-14
4
6
10
12
14
time (seconds)
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An object is hanging vertically on a rubber cord while oscillating up and down. In a coordinate system with the y axis pointing vertically up, the velocity of the object (in m/s) is shown below. 14 12 10 8 6 4 2 2 -4 -6 -8 -10 -12 -14 4 6 10 12 14 time (seconds)

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Expert Answer

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Step 1

The figure we have been given is:

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14 AA 12 10 8 6 4 6 -8 10 -12 -14 10 12 14 tine (seconds) (s/u)

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Step 2

Part(a)

We can conclude the slope of the tangent describes its acceleration from the above figure. Also, since the final velocity vf is positive and initial velocity vi is negative, also │vf│>│vi│ hence, the average acceleration (aavg) is positive (UP) for a given time.

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.V-ν αpg Ξ+ve Δί

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Step 3

Part(b)

The net displacement (s) from the above graph can be given by the area under the curve defined as...

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v dt = +ve

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