An object is moving along a path that can be described as f(x)= = meters, where x is in seconds and f(x) is in meters. What is the object's instantaneous rate of change at x = 1.5 seconds? O The object's instantaneous rate of change at x = 1.5 s is meters per second. O The object's instantaneous rate of change at x = 1.5 s is - meters per second. O The object's instantaneous rate of change at x = 1.5 s is - meters per second. O The object's instantaneous rate of change at x = 1.5 s is meters per second.

Q: Estimate the instantaneous rate of change at x= 1 for Ax) = /x + 1. a) -2 b) -0.5 c) 0.5 d) 2

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Q: 1. Use the Difference Quotient to find the instantaneous rate of change of 2. f(x) = -5x2 - x at x…

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Q: 5. Find the instantaneous rate of change of 1 g(x) = 2x – 32x° + 17x² – 9x + 4 at x = 2

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A: Proceed as shown below...

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Q: Find the instantaneous rate of change for the function at the given value. f(x) =x + 4x at x= - 4…

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Q: We are given f(x) = 9x2 and f '(x) = 18x. Find the instantaneous rate of change of f(x) at x = 2.

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A:

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A:

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A:

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Q: If f(x) = 5x2 − x3, what is the rate of change of f '(x) at (2, 12)?

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Q: The monthly output at the Olek Carpet Mill is Q(x) = 15,000 + 2x2 units,    (40 ≤ x ≤ 60) where x…

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A:

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A:

Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.