An object with a mass of 10.00kg is launched from the ground with an initial upward velocity of 95.00m/s near the surface of Earth. Consider a linear model of the air resistance, kv, with v being the variable velocity and k = 0.0365 kg/s?. Take the ground as the origin and upwards as positive direction. 1. Which of the following best describes the DE relating to the problem? Let t be the time, g be the acceleration due to gravity. a. -10.00- 3.285 = 10.00 dv/dt b. -10.00g +0.0365v = 10.00 dvldt c. -10.00g - 0.0365v = 10.00 du/dt d. -10.00g - 3.285 = -10.00dv/dt %3D 2 Which of the following is closest to the general solution of the linear DE model, velocity as a function of time? Let C be a real constant, exp()3e0 a. v(t) = 1.346t + C b. v(t) = -2688+Cexp(t/274.0) c. v(t) = -2688+Cexp(-1/10.00) d. v(t) = -2688+Cexp(-t/274.0)
An object with a mass of 10.00kg is launched from the ground with an initial upward velocity of 95.00m/s near the surface of Earth. Consider a linear model of the air resistance, kv, with v being the variable velocity and k = 0.0365 kg/s?. Take the ground as the origin and upwards as positive direction. 1. Which of the following best describes the DE relating to the problem? Let t be the time, g be the acceleration due to gravity. a. -10.00- 3.285 = 10.00 dv/dt b. -10.00g +0.0365v = 10.00 dvldt c. -10.00g - 0.0365v = 10.00 du/dt d. -10.00g - 3.285 = -10.00dv/dt %3D 2 Which of the following is closest to the general solution of the linear DE model, velocity as a function of time? Let C be a real constant, exp()3e0 a. v(t) = 1.346t + C b. v(t) = -2688+Cexp(t/274.0) c. v(t) = -2688+Cexp(-1/10.00) d. v(t) = -2688+Cexp(-t/274.0)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:An object with a mass of 10.00kg is launched from the ground with an initial upward velocity of 95.00m/s near
the surface of Earth. Consider a linear model of the air resistance, kv, with v being the variable velocity and k =
0.0365 kg/s?. Take the ground as the origin and upwards as positive direction.
1.
acceleration due to gravity.
Which of the following best describes the DE relating to the problem? Let t be the time, g be the
a. -10.00- 3.285 = 10.00 dv/dt
b. -10.00g +0.0365v = 10.00 dv/dt
c. -10.00g - 0.0365v = 10.00 dv/dt
d. -10.00g - 3.285 = -10.00dv/dt
2
Which of the following is closest to the general solution of the linear DE model, velocity as a function of
time? Let C be a real constant, exp()%3e0
a. v(t) = 1.346t + C
b. v(t) = -2688+Cexp(t/274.0)
c. v(t) = -2688+Cexp(-1/10.00)
d. v(t) = -2688+Cexp(-1/274.0)
%3D
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