An unknown planet (mass is equal to 4.26 x 10^24 kg) is orbiting around the sun (mass of the sun is equal to 6.623703×1035kg). Knowing that the gravitational force between the unknown planet and the sun is (5.18 x 10^9)N, is the unknown planet nearer or farther to the sun compared to earth? (earth's distance to sun is 1 AU) Express your answer in terms of astronomical units or AU (1AU = 1.496 x 108 km). Assuming that the sun is fixated at a center point, calculate the area (in of the unknown planet's orbit (assume that the orbit is circle).

An unknown planet (mass is equal to 4.26 x 10^24 kg) is orbiting around the sun (mass of the sun is equal to 6.623703×1035kg). Knowing that the gravitational force between the unknown planet and the sun is (5.18 x 10^9)N, is the unknown planet nearer or farther to the sun compared to earth? (earth's distance to sun is 1 AU) Express your answer in terms of astronomical units or AU (1AU = 1.496 x 108 km). Assuming that the sun is fixated at a center point, calculate the area (in of the unknown planet's orbit (assume that the orbit is circle).

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom

Section: Chapter Questions

Problem 21P: Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr....

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Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 1011 m is the mean EarthSun distance.) How far from the Sun will Halleys comet travel before it starts its return journey?
At their closest approach, Venus and earth are 4.20x 10^10m apart. The mass of Venus is 4.87x 10^24kg, the mass of earth is 5.97x 10^24 kg and G=6.67x10^-11N m^2/kg2. What is the magnitude of the gravitational force exerted by Venus on earth at that point?
Find the force of gravity between Earth and the Sun (Sun's mass = 2.0×10302.0×10^30 kg; average Earth-Sun distance = 1.5×10111.5×10^11 m).
What is the gravitational force acting between Earth [mass = 5.98 c 10^24 kg] and a 25200 kg object? Use the radius of Earth (6.38 x 10^6 m) as the distance between the two objects.
Assume the earth's mass is 85.47 x 1025 kg, and radius is 51.93 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.
if two objects each with a mass of 2.0x10^2kg. produce gravitational force between them of 3.75x 10^6N. What is the distance between them?
Use Newton's Universal Gravitation Formula to determine the gravitational force of attraction between the earth and the moon given: m(moon)=7.35 x 10^22 kg. The mass of the earth is m(earth) = 5.98 x 10^24 kg. The distance between centers of the earth and moon is r = 3.92 x 10^8 m. Use Newton's gravitation equation F = G (m(1) x m(2))/r^2
2 700kg masses (1543lb) are separated by a distance of 30m. Use newton's law of gravitation find the magnitude of the gravitational force exerted by one mass on the other. Where G = 6.67 x 10^-11 N m^2/ kg^2 Please solve
The masses of the Moon and Earth are 7.4 ✕ 1022 kg and 6 ✕ 1024 kg, respectively. The Earth-Moon distance is 3.8 ✕ 108 m. What is the size of the gravitational force between the Earth and the Moon?
Two objects feel a gravitational force of 948 N when separated by a distance of 7x106.46 meters. What is the mass of the second object, in kilograms, if the first object’s mass is 2.63x1024 kg?
If a satellite circulate around the earth at a height of 2,317.84 km above the earth's surface, given the earth radius is 3958.8 miles and mass is 5.98 x1024 kg, use G=6.67x 10 -11 Nm2/kg2, find the period of this satellite in unit hours?
Use Newton’s universal gravitation formula to determine the gravitational force of attraction between the earth and the moon given: mass (moon) m(moon)=7.35 x 10^22kg the mass of the earth is m(earth)=5.98 x 10^24kg the distance between centers of the earth and moon is r=3.92 x 10^8 m use Newton gravitation equation F=G(m(1) x m(2))/r^2