Question

Asked Oct 22, 2019

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An unmarked police car traveling a constant 90 km/h is passed by a speeder. Precisely 1.00 s after the speeder passes, the police officer steps on the accelerator. If the police car accelerates uniformly at 3.00 m/s2 and overtakes the speeder after accelerating for 9.00 s , what was the speeder's speed?

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Step 1

Let u_{p} is the initial speed of the police car, u_{s} be the speed of the speeder, a_{p} be the acceleration of the police car, t_{1} be the time after which police car starts accelerating, t_{2} be the time for which the police car accelerates, s_{1p}, s_{1s} be the distance travelled by police car and the speeder respectively in time t_{1}, and s_{2p}, s_{2s} be the distance travelled by the police car and speeder in time t_{2}.

Write the given values of question.

Step 2

Write the expression to find the distance travelled by police car and speeder in time t_{1}.

Step 3

Write the expression to find the distance travelled by...

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