and the series 2 ) п? 1. For all n п > 2, n3–5 converges, so by the Comparison Test, n2 the series > п converges. п3—5 arctan(n) and the series :2 converges, so by the Comparison 2. For all n > 1, n3 n3 2n3 arctan(n) Test, the series >) converges. n3 In(n) 3. For all n > 2, , and the series E- diverges, so by the Comparison Test, the п п In(n) diverges. series E 2, and the series 2 >- diverges, so by the Comparison Test, 4. For all n > 1, n In(n) the series > n In(n) diverges. In(n) 5. For all n> 2, n2 and the series >, n2 | converges, so by the Comparison Test, п2 In(n) the series > converges. n2 6. For all n> 1, and the series > n2 п converges, so by the Comparison Test, 3-n3 n2 the series > 3-n3 converges.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 41E
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ARE STATEMENTS ON IMAGE TRUE OR FALSE?

and the series 2 )
п?
1. For all n
п
> 2,
n3–5
converges, so by the Comparison Test,
n2
the series >
п
converges.
п3—5
arctan(n)
and the series :2 converges, so by the Comparison
2. For all n > 1,
n3
n3
2n3
arctan(n)
Test, the series >)
converges.
n3
In(n)
3. For all n > 2,
, and the series E- diverges, so by the Comparison Test, the
п
п
In(n)
diverges.
series E
2, and the series 2 >- diverges, so by the Comparison Test,
4. For all n > 1,
n In(n)
the series >
n In(n)
diverges.
In(n)
5. For all n> 2,
n2
and the series >,
n2
|
converges, so by the Comparison Test,
п2
In(n)
the series >
converges.
n2
6. For all n> 1,
and the series >
n2
п
converges, so by the Comparison Test,
3-n3
n2
the series >
3-n3
converges.
Transcribed Image Text:and the series 2 ) п? 1. For all n п > 2, n3–5 converges, so by the Comparison Test, n2 the series > п converges. п3—5 arctan(n) and the series :2 converges, so by the Comparison 2. For all n > 1, n3 n3 2n3 arctan(n) Test, the series >) converges. n3 In(n) 3. For all n > 2, , and the series E- diverges, so by the Comparison Test, the п п In(n) diverges. series E 2, and the series 2 >- diverges, so by the Comparison Test, 4. For all n > 1, n In(n) the series > n In(n) diverges. In(n) 5. For all n> 2, n2 and the series >, n2 | converges, so by the Comparison Test, п2 In(n) the series > converges. n2 6. For all n> 1, and the series > n2 п converges, so by the Comparison Test, 3-n3 n2 the series > 3-n3 converges.
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