Question

A particular class has 10 students. Suppose that the probability of getting an A in this class is 30% (or rather 3 out of 10) and the probability of getting a B is 40% (or rather 4 out of 10). We want to run a simulation to see how likely this is to occur by chance.

Part a: Using single digits from a section of the random digit table, describe how you will run the simulation.

Part b: Using line 113 from the random digit table (given below), carry out the simulation with 3 runs.

--Line | | | | | | | |

--113 | 61372 | 26590 | 75157 | 57974 | 20862 | 66909 | 88860 | 00930

Part c: Based on your simulation, how many of students got an A for each run? How many of the students in the simulation got a B?

Step 1

Part a:

- The digits from 0 to 9 will be equally likely.
- Each of the digits are equally likely.
- Before starting the procedure, some of the digit will be allocated as the outcome.
- From the random number table, one digit will be taken and it will be checked whether it is matching with the number or not.

The probability of getting an A in class is 30% (or rather 3 out of 10) and the probability of getting a B is 40% (or rather 4 out of 10).

Let 0 to 9 digits are the 10 students.

It is assigned that if from the random number table, 1, 2, 3 arise, then ‘A’.

If 4, 5, 6, 7 arise, then it will be marked as ‘B’.

Otherwise other (×).

Now from random numbers, each digit will be chosen, and will be checked whether it is matching with the assigned grade ‘A’ or ‘B’ or not. If the random number is not matching with the assigned digit the number will be cut and next one will be considered.

Step 2

Par b:

From the random number table we have to take 10 random numbers for each run.

Step 3

Part c:

From the result of part b, it can be observed that,

From first run, the number of A is 4, the number of B is 4.

From second r...

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