Application: Below is an object similar to the "arch" in St. Louis. 1) Convert each end point of the arch into a location. 2) Then convert the top of the arch into a location. 3) Use the 3 locations and your calculator to convert the arch into a mathematical formula. y A 630 ft 630 ft Oy = 3x2 - 485x + 20 O y= -x2 + 315x y = -0.006x2 + 4x O y- (x- 315)2 + 630

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 72E
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Application: Below is an object similar to the "arch" in St. Louis.
1) Convert each end point of the arch into a location.
2) Then convert the top of the arch into a location.
3) Use the 3 locations and your calculator to convert the arch into a mathematical formula.
ov
yA
630 ft
630 ft
O y = 3x2 - 485x + 20
y= -x2 + 315x
y = -0.006x2 + 4x
y (x-315)2 + 630
Transcribed Image Text:Application: Below is an object similar to the "arch" in St. Louis. 1) Convert each end point of the arch into a location. 2) Then convert the top of the arch into a location. 3) Use the 3 locations and your calculator to convert the arch into a mathematical formula. ov yA 630 ft 630 ft O y = 3x2 - 485x + 20 y= -x2 + 315x y = -0.006x2 + 4x y (x-315)2 + 630
Application: Now that you have the formula for the arch, use it to find the path length of the arch.
1405.55 ft
843.59 ft
2515.49 ft
293707.49 ft
Transcribed Image Text:Application: Now that you have the formula for the arch, use it to find the path length of the arch. 1405.55 ft 843.59 ft 2515.49 ft 293707.49 ft
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