Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H2O). If 10,1 gof water is produced from the reaction of 28.1 g of hydrochloric acid and 40.0 g of sodium hydroxide, calculate the percent yield of water.Be sure your answer has the correct number of significant digits in it.X?Submit AssignmentTerms of UsePrivacy2019 McGraw-Hill Education All Rights Reserved.MacBook ProDIIDDO00O00F12F9F10F11escF6F7F8F2F3F4F5F1%7

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Asked Oct 28, 2019
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Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H2O). If 10,1 g
of water is produced from the reaction of 28.1 g of hydrochloric acid and 40.0 g of sodium hydroxide, calculate the percent yield of water.
Be sure your answer has the correct number of significant digits in it.
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Aqueous hydrochloric acid (HCI) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium chloride (NaCl) and liquid water (H2O). If 10,1 g of water is produced from the reaction of 28.1 g of hydrochloric acid and 40.0 g of sodium hydroxide, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it. X ? Submit Assignment Terms of Use Privacy 2019 McGraw-Hill Education All Rights Reserved. MacBook Pro DII DD O00 O00 F12 F9 F10 F11 esc F6 F7 F8 F2 F3 F4 F5 F1 % 7

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Expert Answer

Step 1

Given:

Mass of water = 10.1 g

Mass of HCl = 28.1 g

Mass of NaOH = 40 g

% yield of water =?

Balanced chemical equation:

HCl + NaOH ------------> NaCl + H2O

Step 2

Calculate the moles of both HCl and NaOH given:

Mass of NaOH = 40 g  = 1 mol.

Mass of HCl = 28.1 g

1 mol. ----------- 36.5 g

? mol. Is ---------- 28.1 g

28.1 X 1 / 36.5

= 0.76 mol.

We need HCl and NaOH in 1:1&...

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