aresin (2x-1) = 1-x 2 arctan

Q: 1. Dx[arcsin(2x + 1)]

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Q: 2x2 dx 5 – x²

A: In the given question we have to find the integration by putting in the integral. So we will…

Q: sin3x dx 1+cos3x х dx x+4

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Q: ( sinh3x cosh³x dx

A: Consider the integration as I=∫sinh3xcosh3xdx

Q: arccos 2x dx 3.

A: We will use integration by parts. The solution is given below.

Q: 1 cos(sec-x) dx 2/V3 xVx²-1

A: Let's find.

Q: sec2 (을) dx 23

A: The given integral is ∫sec24x2x3dx.

Q: | (sinh x)(coth’x + csch3x)

A: The solution is given in the next step.

Q: sin S S. cossx (3-2secs)

A: The given integral is ∫sin 5xcos2(5x)3-2sec(5x)dx The derivative formula is ddx(sec ax)=atan…

Q: 4 f sin(5 – 6x) sin (6x – 4)dx -

A: Here limit are not given so we integrate only without using of limit.

Q: csc squared x/2 = 2/1-cosx verify with steps

A: To Verify:

Q: 3- Sin4x dx S 3-Sin4x dx ノo

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Q: इसे १५ Sin 2X *3 tant 2X Lind ds_2

A: Given that the function is   y = 2sin2 2x × 3tan-1 2x To find the dydx

Q: sin 3x dx 3-10cos3x 10.

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Q: Integrate √2 2 | sin x 2 √1-x² dx

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Q: sech²x -dx tanh(x)v1-tanh²x ix.

A: Solution is given below:

Q: Solve the equation for x  arcsin√2x = arccos√x

A: The given equation is sin-12x=cos-1x

Q: 2x+5 dx = AV7- 6x - x2 + B sin - (**)- 1. Vア-6xーx2 +C

A: ∫2x+57-6x-x2

Q: csch (2 sin2x)dx 1. 1– 4x²

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Q: 4 fcos 3x sin³ 3x dx

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Q: ∫√1 - sin^2 x dx

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Q: I3Jsin'x cos x dx .6,

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Q: Integral of tan^4(x)sec^6(x)dx

A: Sincesec2x=1+tan2xTherefore,

Q: Evaluate the integral.

A: Given integral is ∫sin2xdx1+cos2x. Consider a=1+cos2x. Then da=-2cosxsinxdxdx=da-sin2x

Q: Ssec*x (Vtan²x + 1) 2. 4 sec' x tan3, dx

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Q: 1. Ssin (2x-1)cos (2x-1)dx

A: 1) Evaluate: ∫sin42x-1cos32x-1dx

Q: у %3DIn(In sec x)

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Q: (cosh ' []] 1s dz

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Q: [17 sin³ x costx dx 5.

A: Given: I=∫17sin3xcos4x dx. To evaluate: Value of integral I.

Q: ( csch (2 sin 2x) dx V1-4x

A: We have to find indefinite integral

Q: ∫cos(15x)cos(4x)dx

A: Integration and differentiation can be considered as inverses of each other. Integration is mainly…

Q: .2 x² arctan(3x) dx %3D

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Q: integrate [(x csc^2 (2x) - x cos (2x)] dx

A: Given problem:-  ∫ [(x csc2(2x) - xcos(2x)] dx

Q: 2Cos 2x- Sin20-2

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Q: sec“ x (Vtan3 x +1) dx (Vtan3, Px+1) 4

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Q: (cotx + tanx)² dx 3 4

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Q: X= sin 2tS In %3D Find dw 2- Cost

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Q: Jam sin(10x) dx

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Q: Secax dx tana x

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Q: Integrate (tanx)^3(secx)^3

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Q: 2. S CoSx+sinx-1

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Q: Differentiate (1 + x2) arctan x-x.

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Q: 2cosx dx 2 1+(sinx)²

A: Please refer the attached image for complete solution.

Q: find integral tan 6 x sec  4 x dx

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Q: [ sec" x (Vtan' x+ 1) +1) dx 2. 4 sec'x 3

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Q: Find the length of the arc y =: 8 1 from X = 1 tox = 4. 4x?

A: Graph: Given: y=x48+14x2. So,          y'=x48+14x2' =x32-12x3.

Q: S secs/2 (금x) tans (글x) dzx

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Q: 9 coshx - 5 sinhx 15 %3D

A: To solve  9coshx-5sinhx=15

Q: SVx² + 10x + 25 dx. (cos4*x – sin4*x)dx dx

A: