Question

Step 1

Consider the key which is thrown from the window as case 1.In this case, the initial velocity of key is zero. According to Newton’s equation of motion, the expression for the distance (*h*_{1}) covered by key is:

Step 2

Consider the key which is thrown from the ground as case 2.In this case, the initial velocity of key is *u*. According to Newton’s equation of motion, the expression for the distance (*h*_{2}) covered by key is:

Step 3

In case 2, the final velocity of the key is zero. So, the ...

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