Question

Asked Nov 9, 2019

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Assume that a procedure yields a binomial distribution with n=579n=579 trials and the probability of success for one trial is p=48%p=48%.

Find the mean for this binomial distribution.*(Round answer to one decimal place.)*

μ=μ=

Find the standard deviation for this distribution.*(Round answer to two decimal places.)*

σ=σ=

Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.

Enter answer as an interval using square-brackets **only with whole numbers**.

usual values =

Step 1

From the given information,

Sample size (*n*) = 579.

Probability of success (*p*) =0.48

Step 2

a)

The mean for this binomial distribution is-

Since, the sample size is large enough thus, by normal approximation to binomial.

Step 3

b)

The standard deviation of for this bino...

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