assume that a sample is used to estimate population proportion p. find the 95% confidence interval for a sample of size 177 with 49 successes. enter the answer as an open-interval.

Q: Construct the 99% confidence interval estimate of the population proportion p if the sample size is…

A: Obtain the 99% confidence interval estimate of the population proportion. The 99% confidence…

Q: Use the given confidence interval to find the margin of error and the sample mean. .734, .760

A: From the given information, the confidence interval is (0.734, 0.760). It can be expressed in,

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.2,20.2) The…

A: Given: confidence interval = (13.2, 20.2)

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: From the provided information, Confidence interval is (0.751, 0.777)

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Obtain the value of margin of error.   The value of margin of error is obtained below as follows:…

Q: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level E=

A: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: The given confidence interval for p is (0.779, 0.803). The value of margin of error is,

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: The margin of error and the sample proportion are calculated by using the given confidence interval…

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,20.7) The…

A:

Q: 1. A consumer watch group interviewed a random sample of 1000 consumers and asked them if they are…

A: Here use confidence interval for population proportion

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,21.9) The…

A:

Q: Construct a 95​% confidence interval of the population proportion using the given information.…

A:

Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion. (0.741,0…

A:

Q: Determine the sample size necessary to construct a 85% confidence interval with an error of 0.07 if…

A: Given,margin of error (E)=0.07sample proportion…

Q: Use the given confidence interval to find the margin of error and thr sample mean. (5.42, 8.56)

A: Obtain the value of margin of error using the confidence limits.   The value of the margin of error…

Q: B. Construct a 95% confidence interval estimate of 4-4, the difference between the mean weight of…

A: Given Information: B) 95% confidence interval estimate of difference between the mean weight of…

Q: Determine the 99.5 percent confidence interval that contains the population variance if the sample…

A:

Q: Assume the population is normally distributed. A 99% confidence level requires a sample size of

A: The formula to compute sample size is,

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: According to the given information, we have Confidence interval = (0.690, 0.718)

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: The formula of the margin of error using the confidence limits is, Where,   UCL denotes the upper…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Given data, Lower limit LL=0.621 Upper limit UL=0.651   Margin of error(E)=? Sample proportion p=?

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: The confidence interval is CI = (0.589,0.619) CI = (LB,UB)

Q: Assume that a sample is being used to estimate a population mean μμ. If n = 29, x¯ = 46, and s =…

A: From the provided information, Sample size (n) = 29 Sample mean (x̅) = 46 Sample standard deviation…

Q: If Xbar=93​, σ=13​, and n=62​, construct a 99​% confidence interval estimate of the population​…

A: Given that  Sample size: n=62 Sample mean: x¯=93 Population standard deviation: σ=13 Confidence…

Q: Determine the margin of error for an 80% confidence interval to estimate the population mean with…

A: Given that  Confidence level (C) = 80%  Population standard deviation (σ) = 48   We know that…

Q: Use the given confidence interval to find the margin of error.and the sample proportion.…

A: Given, Confidence interval (0.741, 0.767) Upper limit U = 0.767 Lower limit L = 0.741

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.0,21.2) The…

A: Confidence Interval C.I. = (13.0, 21.2)

Q: If X=72​, σ=13​, and n=66​, construct a 95​% confidence interval estimate of the population​…

A:

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: Assume that a sample is being used to estimate a population mean μμ. If n = 19, x¯ = 43, and s = 3,…

A:

Q: Use the given confidence interval to find the margin of error and the sample mean. (71.7, 87.3)

A:

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: Use the given confidence interval to find the margin of error and the sample mean.  (4.81, 8.09)

A: The confidence interval is given by (4.81, 8.09)

Q: Use the confidence interval to find the margin of error and the sample mean.   (.364,0.500)

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: According to the given information, we have Given confidence interval = (0.675, 0.703)

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given data n=1026 x=520 confidence interval=95%

Q: find tc for a 95% confidence level when the sample size is 6.

A: level of significance, alpha = 0.05from standard normal table, two tailed t alpha/2 with n-1 = 6 d.f…

Q: identify the population proportion, the value of margin of error E, and construct the confidence…

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Here, the confidence interval is (0.591, 0.621). The margin of error is given below: Margin of…

Q: If X-bar = 125, σ = 24, and n = 36, construct a 99% confidence interval estimate for the population…

A: Given: X-bar = 125, σ = 24, n = 36.

Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…

A: Given,confidence interval is (14.2 , 24.0)

Q: Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence…

A: Solution: From the given information, p=0.85, n=201 and the confidence level is 0.995.

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Given: Confidence interval = (0.705, 0.733) Thus, Lower limit = 0.705 Upper limit = 0.733

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,21.9)

A: Given confidence interval (13.5, 21.9)

Q: If X=80​, σ=11​,and n=62​,construct a 95​% confidence interval estimate of the population​ mean, μ.…

A: Given,sample size(n)=62sample mean(x¯)=80standard deviation(σ)=11α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Let the confidence interval for population proportion is (a, b) Margin of Error : E =b-a2 Sample…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Solution-: Given: C.I. is (0.702,0.728) Where, LL=0.702, UL=0.728  Find M.E. and  ,

Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…

A: Sample mean = (upper limit+lower limit)/2

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.