Assume that a satellite of mass M is orbiting the earth at a distance r from the center of the earth with speed Ve. An identical satellite is orbiting the moon at the same distance with a speed Vm. How does the time Tm it takes the satellite circling the moon to make one revolution compare to the time Te it takes the satellite orbiting the earth to make one revolution?  The answer is that Tm is greater than Te but I do not understand why... Thank you :)

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A: (a) orbital period of the star T=2πr3GM=2π6.0×104 ly39.461×1015 m1 ly36.67×10-11…

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A: mass of satellite (m) = 2600 kg altitude of satellite above the surface of earth (h) = 450 km

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Q: Question 1 and 2

A: 1. Orbital velocity is given by,

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A: Let us assume that the mass of the satellite be m It centripetal force=mv2Rwhere v is the orbital…

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A: mass of milky way (m) = 8×1011 solar masses = 8×1011×2×1030kg = 16×1041 kg distance (d) = 5.6×104…

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A: r=Rearth+h=6400 km+450 km=6850 km

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A: Orbital velocity  V0=GM/r             r= R+H     M= Mass of Mars GIVEN mmars = 6.4191 x 1023 kgrmars…

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Q: NASA is expected to send a 2600-kg satellite 450 km above the earth's surface. (a) What is its…

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A: Given data: Mass of satellite, m=1000 kg Time period, T=300 min=300×60 s=18×103 s Mass of Earth,…