Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Use the p value method and fill in the blanks to address the claim.In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures.518  548   561   523   536499   538   557   528   563At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours.Please answer the following with details and the calculator steps:Claim: ____________________________________H0           H1u0             tList           FreqpSince p ______ a, we ___________ the null hypothesis.Final statement: _____________________________________

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Asked Nov 8, 2019
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Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Use the p value method and fill in the blanks to address the claim.

In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures.

518  548   561   523   536

499   538   557   528   563

At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours.

Please answer the following with details and the calculator steps:

Claim: ____________________________________

H0           H1

u0             t

List           Freq

p

Since p ______ a, we ___________ the null hypothesis.

Final statement: _____________________________________

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Expert Answer

Step 1

Claim: The mean time between failures is greater than 520 hours.

Step 2

H0: µ = 520 hours

That is, the mean time between failures is 520 hours.

Alternative hypothesis:

H1: µ > 520 hours

That is, the mean time between failures is greater than 520 hours..

Since, the alternative hypothesis states that µ > 520 hours, it is right-tailed test.

Step 3

Sampling distribution of the test:

Since the population standard deviation is unknown, it is appropriate to apply t-test.

Test statistic for t-test:

Here, using EXCEL function, the sample mean, x-bar (u0) is 537.1 (“=AVERAGE(B1:B10)”) and sample standard deviation, s is ...

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537.1-520 20.7 vi0 17.1 6.55 =2.61

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