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Assume that his shots are Bernoulli trials, and that he makes 2 in 8 of his shots.How many three point shots must the player attempt so that the probability of his hitting at least one of them is at least 0.76?

Question

 Assume that his shots are Bernoulli trials, and that he makes 2 in 8 of his shots.

How many three point shots must the player attempt so that the probability of his hitting at least one of them is at least 0.76?

check_circleAnswer
Step 1

It is given that shots are Bernoulli trials and he makes 2 in 8 of his shots. The probability of hitting at least one them is at least 0.76.

 

Step 2

Calculation:

From the given data it is clear that the number of shots follow B(...

P(hitting at least one) 0.76
1-P(not hitting) 0.76
P(not hitting) 0.24
>
n
6
<0.24
п
6
nlog
|s log (0.24)
log (0.24)
n 2
6
log
8
4.96
help_outline

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P(hitting at least one) 0.76 1-P(not hitting) 0.76 P(not hitting) 0.24 > n 6 <0.24 п 6 nlog |s log (0.24) log (0.24) n 2 6 log 8 4.96

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