Question
Asked Dec 4, 2019
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Assume that the area of the triangle BAE is 37
cm2, that the area of the trapezoid ABDF is 86
cm2, and that the area of triangle BDC is twice
that of triangle AEF
А
В
13 cm
Find the area of triangle BDC
с
F E
D
cm2
The area of triangle BDC is
(Round to the nearest integer as needed.)
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Assume that the area of the triangle BAE is 37 cm2, that the area of the trapezoid ABDF is 86 cm2, and that the area of triangle BDC is twice that of triangle AEF А В 13 cm Find the area of triangle BDC с F E D cm2 The area of triangle BDC is (Round to the nearest integer as needed.)

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Expert Answer

Step 1

Consider the given diagram of the question,

Given Area of the triangle BAE = 37 cm2

According to the given diagram,

Area of rectangle ABDE = area of triangle BAE + area of triangle BDE

Since, BE is the diagonal of the rectangle ABDE.

So, area of triangle BAE = area of triangle BDE

Thus, Area of rectangle ABDE = 2(area of triangle BAE)

                                                                   = 2x37

                                                                  = 74 cm2

Step 2

Given Area of trapezoid ABDF = 86 cm2

Now, according to the given diagram,

Area of triangle AEF = Area of trapezoid ABDF - Area of rectangle ABDE

                                  &n...

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