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Assume that the box contains balls numbered from 1 through 26, and that 3 are selected. A random variable XX is defined as 1 times the number of odd balls selected, plus 2 times the number of even.How many different values are possible for the random variable XX? Fill in the table below to complete the probability density function. Be certain to list the values of XX in ascending order. Value of XProbability N

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Asked Oct 6, 2019

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Assume that the box contains balls numbered from 1 through 26, and that 3 are selected. A random variable XX is defined as 1 times the number of odd balls selected, plus 2 times the number of even.

How many different values are possible for the random variable XX?

Fill in the table below to complete the probability density function. Be certain to list the values of XX in ascending order.

Value of X	Probability

Expert Answer

Step 1

As per the question, the number can be either odd or even and 3 are selected

So total possible combinations are 23= 8

Out of 26, there are 13 odd and ...

Odd no
Combinations
Even no
х
(o, o, o)
(0,0,e)
(0,е,0)
(e,o,0)
(e,e,e)
(e,e,0)
(е,0,е)
(0,e,e)
3
0
3 x 10 x 2 = 3
2
1
2 x 11 x 2 = 4
2
1
2 x 1 1 x 2 = 4
2
1
2 x 11 x 2 = 4
0 x 13 x 2 = 6
1 x 12 x 2 = 5
1 x 1 2 x 2 = 5
0
3
-
1
2
1
2
1
1 x 12 x 2 = 5 — Image Transcription
Odd no Combinations Even no х (o, o, o) (0,0,e) (0,е,0) (e,o,0) (e,e,e) (e,e,0) (е,0,е) (0,e,e) 3 0 3 x 10 x 2 = 3 2 1 2 x 11 x 2 = 4 2 1 2 x 1 1 x 2 = 4 2 1 2 x 11 x 2 = 4 0 x 13 x 2 = 6 1 x 12 x 2 = 5 1 x 1 2 x 2 = 5 0 3 - 1 2 1 2 1 1 x 12 x 2 = 5

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