Assume that the physical arrangement of the coils results in P1=P2. If coil 1 has 500 turns, how many turns does coil 2 have?
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Assume that the physical arrangement of the coils results in P1=P2. If coil 1 has 500 turns, how many turns does coil 2 have?
If P1 = P2
I12R1= I22R2
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- A coil of resistance 100W is placed in a magnetic field of 1mW. The coil has 100 turns and a galvanometer of 400W resistance is connected in series with it. Find the average emf and the current if the coil is move in 1/10th second from the given field to a field of 0.2mWb.1... Why do we use round-shaped coils (I.e., Round shaped turns in the coils) in both the primary and secondary circuits [If those coils were not round-shaped, what would be the problem]? Must show the draw figures 2.... Write down major differences between conducting and displacement current densities with proper figures.A coil with 2000 turns has a length of 20mm and a winding thickness of 5mm. If the coil carries 5mA current, which of the following is the value of mmf (magnetomotive force) produced? Please choose one: a.2000 A.t. b. 500 A.t C. 10 A.t. D.None
- A 200-turn coil is immersed in a 60-Hz flux with an effective value of 4 mWb. Obtain an expression for the instantaneous value of the induced emf. If a voltmeter is connected between its two ends, what will be the reading on the voltmeter?A coil is made up of 1000 turns of 0.5 mm^2 cross-sectional area copper wire. The average length each turn is 100 cm, and the copper resistivity is 0.02 µΩ m at 20 degrees Celsius. Determine the coil's resistance. Find the resistance of the coil at 20 degrees Celsius. * 30 ohm 40 ohm 50 ohm 60 ohm Find the resistance of the coil at 100 degrees Celsius if the temperature coefficient of resistance at 30 degrees Celsius is 3.7807 x 10^(-3) per degrees Celsius * 32.57 ohm 42.57 ohm 52.57ohm 62.57 ohmThe coil of a moving-coil voltmeter is25 mm long and 25 mm wide and has 60 turns on it. The control spring exerts a torque of 1.58 x 10 Nm when the deflection is 100 divisions on full scale. If the flux density of the magnetic field in the air gap is 5 wb/m², estimate the resistance that must be put in series with the coil to give one volt per division. The resistance of the voltmeter coil may be neglected
- explain why Two coils are said to be mutually coupled if the magnetic flux Ø emanating from one pass through the other. The mutual inductance between the two coils is given by M=ksquare root of L1xL2The two coils A and B wound coaxially on an insulating cylinder. It will be evident that the fluxes produced by a current i through the two coils are in the same direction, and the coils are said to be cumulatively coupled. If the direction of the current in B relative to that in A is reverse, then coils are said to be differential coupling. Suppose A and B to have self-inductances and henrys respectively and a mutual inductance M henrys. If two coils are connected in series, their effective inductance is found to be 12.0H. However, when the connections to one coil are reversed, the effective inductance is 8.0 H. If the coefficient of coupling is 0.6. a) Show that the total inductance of inductively coupled circuits is + ± 2M b) Calculate the self-inductance of each coil and the mutual inductance.Field current If can be varied by varying the resistance of field resistance which is connected in series with the field circuit. Select one: True False
- A 1Φ, 120 V rms, 60 Hz supply is connected to the coil, the coil has 200 turns. The parameters of the core are as follows:Length of core =100 cm Cross-sectional area of core = 20 cm2 Relative permeability of core = 2500 (a) Obtain an expression for the flux density in the core. (b) Obtain an expression for the current in the coil.An iron ring of mean length 50 cms has an air gap of 1 mm and a winding of 200 turns. If the permeability of iron is 300 when a current of 1 A flows through the coil, find the flux density.Given a two magnetically coupled coils -coils physical structure is P11=P22 -self-inductance of coil 1: 288mH -coefficient of coupling: 0.75 -mutual inductance: 90mH -wound on a nonmagnetic core Determine L2 Blank 1 milli If N1 =1200, what is the value of P2? Blank 2 micro