Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air resistance.) A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 62 feet per second. How high will the ball go? (Round your answer to two decimal places.) ft Read It Talk to a Tutor Need Help?

Q: Assume the acceleration of the object is  a(t) = −32  feet per second per second. (Neglect air…

A: y=12at2+v0t+s0 here we have  a=-32 v0=48 s0=6 y=12-32t2+48t+6 y=-16t2+48t+6

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Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A:

Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A: We know that, from equation of motion, v2=u2+2as         ⋯⋯1 Where v=final velocity, u=initial…

Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A: topic:- calculus

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A: Given that: height of the ball at any time t will be:            h(t)=80t-16t2

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Q: Assume the acceleration of the object is a(t) = -9.8 meters per second per second. (Neglect air…

A: As the body is thrown upward g acts downward so the value of acceleration is negative.

Q: Assume the acceleration of the object is a(t) = -9.8 meters per second per second. (Neglect air…

A: If you like the solution then please give it a thumbs up... The Answer is:           Velocity =…

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Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A:

Q: Use a(t)= - 32 ft/sec? as the acceleration due to gravity. A ball is thrown vertically upward from a…

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Q: student drops a pen from a classroom window on the fourth floor of the mathematics building. If the…

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Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A: Given s=-32  ftu=16 ft/seca=-32 ft/sec2

Q: Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air…

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Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A: Explanation of the answer is as follows

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Q: Assume the acceleration of the object is a(t) = -32 feet per second per second. (Neglect air…

A: Aim: To determine the maximum height attained by the ball.   Nomenclature: acceleration at any time…

Q: Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air…

A: From the given question we get, a(t)=y''(t)=-32 ft/sec2v(0)=y'(0)=66 ft/secy(0)=6 ft