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- What is an nth partial sum?2. Consider the series partial sum of infinity to k = 2 of (k^4 + 2k^2 + k −3)^(1/2)/(k^3 + 2k^2 + 6) .(a) Explain why the Limit Comparison Test is a good choice for determining convergence/divergence of theseries.(b) Use the Limit Comparison Test to determine whether the converges or diverges. Make sure to carefully apply the test and to explain your choice of a comparison series.2). Compute the general term an of the series with the given partial sum Sn. Sn = 2 − n + 2 2n , n ≥ 1 an = If the sequence of partial sums converges, find its limit S. (If the quantity diverges, enter DIVERGES.) S = please show step by step .
- By the alternating series test, the series converges. Find its sum and the first partial fraction decomposition. Find the limit of the partial sums.1). Compute the general term an of the series with the given partial sum Sn. Sn = n(n + 1) 2 , n ≥ 1 an = If the sequence of partial sums converges, find its limit S. (If the quantity diverges, enter DIVERGES.) S = please show step by step .Find the value that the below series converges to using partial fraction decomposition. Please provide detailed steps with explanation. sum from n=1 to infinity (6)/((5n+5)(n+2))
- First four partial sums of the series, then find the limit as n approaches infinity if the sequence of partial sums?3) . Calculate the first three partial sums of the series. ∞ n = 1 1 (n + 4)(n + 5) Hint: Use a partial fraction decomposition like that for ∞ n = 1 1 n(n + 1) . Use the sequence of partial sums to determine whether the series converges or diverges. please show step by step .2) Compute the general term an of the series with the given partial sum Sn. Sn = 2 − n + 2 2n , n ≥ 1 an = If the sequence of partial sums converges, find its limit S. (If the quantity diverges, enter DIVERGES.) S = please do step by step
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