Assuming that the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample size of n = 8. 1, 2, 3, 4, 5, 6, 7, and 19 e In the given data, replace the value 19 with 8 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 95% confidence interval for the population mean, using the formula or technology. OSusO (Round to two decimal places as needed.)

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: From the provided information, Sample size (n) = 59 and x = 29 The sample proportion can be obtained…

Q: To estimate the average gestation time (time being carried in the womb between conception and birth)…

A:

Q: Construct the confidence interval for the population mean mean μ.  c=0.90​, x (x-bar)=16.2​, σ=10.0…

A: The 90% confidence interval for the population mean µ is calculated as follows:

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A: Given  95% CI for population proportion (p) (0.529,0.627)

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A: Given data,n=100x=22σ=3z-value at 95% confidence is Zc=1.96

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A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given Information n =87 x =48

Q: Use the given confidence interval to find the margin of error and the sample mean. (15.3,22.3)

A: We have to find sample mean and margin of error..

Q: If n = 20, = 43, and s = at a 90% confidence level. Assume the data came from a 4, construct a…

A: From the provided information, Sample size (n) = 20 Sample mean (x̄) = 43 Standard deviation (s) = 4

Q: Assuming that the population is normally​ distributed, construct a 95% confidence interval for the…

A: Solution

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: The sample size n=92. The sample proportion is 61/92. The absolute value of Zα/2 is 1.645 using the…

Q: Use the given confidence interval to find the margin of error and the sample mean . (12.9, 20.1)

A: See the handwritten solution

Q: In a survey, the planning value for the population proportions P* = 0.5. How large a sample should…

A: Given,population proportions (p*)=0.5margin of error (E)=0.04α=1-0.90=0.1α2=0.05Z0.05=1.645  (from…

Q: Determine the confidence interval of the following: Given the information: the sampled population…

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Obtain 95% confidence interval for the population proportion p. The 95% confidence interval for…

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A:

Q: Use the given confidence interval to find the population proportion margin of error. 0.54<p<0.68

A: Given: 0.54&lt;p&lt;0.68 To find: Margin of error

Q: Suppose we wish to find the required sample size find a 90% confidence interval for the population…

A:

Q: Suppose that you had collected the following sample data (in inches) on the diameters of tree…

A: Given that you had collected the following sample data (in inches) on the diameters of tree trunks,…

Q: c. Find the confidence interval for the population mean with confidence level of 99%

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A:

Q: Given the following confidence interval for a population mean, compute the margin of error, E.…

A: According to the provided information, 10.18&lt;μ&lt;11.90

Q: b. Calculate a 95% confidence interval for the proportion of the population who have been told they…

A: b. A sample 1,414 adults are taken for a survey to ask the question that "Have you ever been told…

Q: 3. Use the given degree of confidence and sample data to construct a confidence interval for the…

A:

Q: Given the information: the sampled population is normally distributed, X– = 36.5, σ = 3, and n = 20.…

A: Given that

Q: A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.16 years…

A: Given: n = 25 X = 33.16 S = 9.89 Formula Used: Confidence Interval = X ± Sntn-1               {When…

Q: Assume that a sample is being used to estimate a population mean μμ. If n = 19, x¯ = 43, and s = 3,…

A:

Q: Assuming that the population is normally distributed, construct a 90% confidence interval for the…

A:

Q: Assuming that the population is normally distributed, construct a 95% confidence interval for the…

A: Given : Data I= 1 , 2 , 3 , 4 , 19 Data II = 1 , 2 , 3 , 4 , 5  Sample size = n = 5

Q: In a survey, the planning value for the population proportion is p* 0.16. How large a sample should…

A: Obtain the sample size of a preliminary estimate for p is 0.16 with the 90% confidence.   The…

Q: Assuming that the population is normally​ distributed, construct a 95% confidence interval for the…

A: We want to calculate 95% confidence interval

Q: 530 males in the sample who gave a numeric response from 0 to 6, the mean was 2.51 and the standard…

A: Provided information is, n =530 x̅ =2.51 s =0.87 90% confidence interval can be calculated as:…

Q: Find the length of the confidence interval given the following data: s (standard deviation) = 6 n…

A:

Q: For the data provided in the table below, find 90%, 95%, and 99% confidence intervals for the mean…

A: Sample x (x-x̄) (x-x̄)^2 1 2.68 -0.7 0.49 2 2.8 -0.58 0.3364 3 2.92 -0.46 0.2116 4 3 -0.38…

Q: use the given degree of confidence and sample date to contruct a confidence interval for the…

A: Sample size = n = 124 Sample number of events = x = 20 Sample proportion = p̂ = x/n = (20/124) =…

Q: a) Using a sample size of 75, construct a 95% confidence interval estimate of the mean birth weight…

A: here given ,  A study has been conducted to verify the mean of birth weight at Apple County. From…

Q: In a random sample of 50 people, the mean body mass index (BMI) was 27.7 and the standard deviation…

A: Given that the sample size is 50, the mean is 27.7 and the standard deviation is 6.12 a) Confidence…

Q: Given below are the number of successes and sample size for a simple random sample from a…

A: Note: Thank you for the question. Since multiple subparts are posted, according to our policy, we…

Q: ence interval for a population mean, compute the margin of error, E. 11.00<μ<13.1411.00<μ<13.14

A: Given the confidence interval 11.00&lt;μ&lt;13.14 Computing the Margin of error is given as below:

Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…

A: Given,confidence interval is (14.2 , 24.0)

Q: Assuming that the population is normally distributed, construct a 90% confidence interval for the…

A: Solution-: We find 90% confidence interval for the data 1,2,3,4,5,6,7,25 Also, we find confidence…

Q: Assuming a population of interest is approximately normally distributed, construct a 95% confidence…

A: Solution: Let X be the random variable. From the given information, x-bar=30, s=3.5 and n=15.

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,21.9)

A: Given confidence interval (13.5, 21.9)

Q: Use the table for t distribution to determine the value of t to construct a confidence interval for…

A: Given, Confidence coefficient: 0.90, and sample size, n = 10 degree of freedom  =n-1=10-1=9

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Solution-: Given: C.I. is (0.702,0.728) Where, LL=0.702, UL=0.728  Find M.E. and  ,

Q: Use the given confidence interval to find the population proportion margin of error. 0.25< P <0.53

A: We have to find  populatiin margin of error...

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Of 293 employees selected randomly from one company, 8.19% of them commute by carpooling.…

Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…

A: Sample mean = (upper limit+lower limit)/2

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.