At 4 p.m. on a winter day, an arctic air mass moved from Kansas into Oklahoma, causing temperatures to plummet. Thetemperature T = T(h) in degrees Fahrenheit h hours after 4 p.m. in Stillwater, Oklahoma, on that day is recorded in the followingtable.HoursT Temperaturesince 4 P.M.620591382263224WarmCold(a) Use functional notation to express the temperature in Stillwater at 5:30 p.mXEstimate the value of the above term. (Round your answer to one decimal place.)OX(b) What was the average rate of change per minute in temperature between 4 p.m. and 5 p.m.? (Round your answer totwo decimal places.)XWhat was the average decrease per minute over that time interval? (Round your answer to two decimal places.)X /min(c) Estimate the temperature at 4:15 p.m. (Round your answer to one decimal place.)X(d) At about what time did the temperature reach the freezing point?630p.mExplain your reasoning.

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Asked Dec 2, 2019
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At 4 p.m. on a winter day, an arctic air mass moved from Kansas into Oklahoma, causing temperatures to plummet. The
temperature T = T(h) in degrees Fahrenheit h hours after 4 p.m. in Stillwater, Oklahoma, on that day is recorded in the following
table.
Hours
T Temperature
since 4 P.M.
62
0
59
1
38
2
26
3
22
4
Warm
Cold
(a) Use functional notation to express the temperature in Stillwater at 5:30 p.m
X
Estimate the value of the above term. (Round your answer to one decimal place.)
O
X
(b) What was the average rate of change per minute in temperature between 4 p.m. and 5 p.m.? (Round your answer to
two decimal places.)
X
What was the average decrease per minute over that time interval? (Round your answer to two decimal places.)
X /min
(c) Estimate the temperature at 4:15 p.m. (Round your answer to one decimal place.)
X
(d) At about what time did the temperature reach the freezing point?
6
30
p.m
Explain your reasoning.
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At 4 p.m. on a winter day, an arctic air mass moved from Kansas into Oklahoma, causing temperatures to plummet. The temperature T = T(h) in degrees Fahrenheit h hours after 4 p.m. in Stillwater, Oklahoma, on that day is recorded in the following table. Hours T Temperature since 4 P.M. 62 0 59 1 38 2 26 3 22 4 Warm Cold (a) Use functional notation to express the temperature in Stillwater at 5:30 p.m X Estimate the value of the above term. (Round your answer to one decimal place.) O X (b) What was the average rate of change per minute in temperature between 4 p.m. and 5 p.m.? (Round your answer to two decimal places.) X What was the average decrease per minute over that time interval? (Round your answer to two decimal places.) X /min (c) Estimate the temperature at 4:15 p.m. (Round your answer to one decimal place.) X (d) At about what time did the temperature reach the freezing point? 6 30 p.m Explain your reasoning.

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Expert Answer

Step 1

The temperature T in Fahrenheit after the time 4 P.M. in hours is shown in the below table.

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Temperature (T) Hours (h) since 4 P.M 0 62 1 59 2 38 26 4 22 Temperature (T) Hours (h) since 4 P.M 0 62 1 59 2 38 3 26 22

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Step 2

The temperature in the still water is given by T(1.5) and the estimate value of it is obtained by taking average as shown.

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T (1)+T(2) T(1.5) 2 59+38 2 T(1.5) 48.5 2

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Step 3

The average rate of change between two ...

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T(h)-т(п) Average rate of change h-h Here h 0, and h 1 T()-т(0) Average rate of change = 1 0 59-62 1 =-3°Fper hour Convert F per hour to 'F per minute F per minute 60 Average rate of change = Averagerate of change = -0.05° F per minute Therefore Average decrease = 0.05°F per minute

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