Question
Asked Oct 20, 2019

At one point in a pipeline the water's speed is 3.00 m/s and the gauge pressure is 5.00×104 Pa. Find the gauge pressure at a second point in the line, 11.0 m lower than the first, if the pipe diameter at the second point is twice that at the first.

check_circleExpert Solution
Step 1

Given,

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Step 2

By applying continuity we can calculate velocity at second point,

3
m/sec
1/2
4 4
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3 m/sec 1/2 4 4

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Step 3

By applying Bernoulli&r...

Р.
+
+Z2
+ Z
Pg 2g
Pg 2g
Р.
+(z-z)
=_
2g 2g
Pg
Pg
3
(3)'
0 x 9.8)(2x9.8)
5x10
Р.
+11=
4
(2x9.8)
Pg
Р.
5.1+0.4311=-
Pg
=16.53m
Pg
P (16.53) (1000)(9.8)
P 16.2 Pa
+
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Р. + +Z2 + Z Pg 2g Pg 2g Р. +(z-z) =_ 2g 2g Pg Pg 3 (3)' 0 x 9.8)(2x9.8) 5x10 Р. +11= 4 (2x9.8) Pg Р. 5.1+0.4311=- Pg =16.53m Pg P (16.53) (1000)(9.8) P 16.2 Pa +

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Fluid Mechanics

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