At time t = 0, a bottle of juice is at 84°F is stood in a mountain stream whose temperature is 50°F. After 5 minutes, its temperature is 75°F. Let H(t) denote the temperature of the juice at time t, in minutes. (a) Write a differential equation for H(t) using Newton's Law of Cooling. Use k as the unknown constant. dH -(k (H – 50)) dt (b) Solve the differential equation. NOTE: Round constants to 5 decimal places if needed. H() — 34 е -0.062t + 50 %3D (c) When will the temperature of the juice have dropped to 56°F? NOTE: Round your answer to the nearest minute. After 28 minutes, the temperature will have dropped to 56°F.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter16: Temperature And The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 2P: Convert the following to equivalent temperatures on the Celsius and Kelvin scales: (a) the normal...
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At time t = 0, a bottle of juice is at 84°F is stood in a mountain
stream whose temperature is 50°F. After 5 minutes, its temperature
is 75°F. Let H(t) denote the temperature of the juice at time t, in
minutes.
(a) Write a differential equation for H(t) using Newton's Law of
Cooling. Use k as the unknown constant.
dH
- (к (Н — 50))
dt
(b) Solve the differential equation.
NOTE: Round constants to 5 decimal places if needed.
H(t)
-0.062t
34 е
+ 50
(c) When will the temperature of the juice have dropped to 56°F?
NOTE: Round your answer to the nearest minute.
After |28
minutes, the temperature will have dropped to
56°F.
Transcribed Image Text:At time t = 0, a bottle of juice is at 84°F is stood in a mountain stream whose temperature is 50°F. After 5 minutes, its temperature is 75°F. Let H(t) denote the temperature of the juice at time t, in minutes. (a) Write a differential equation for H(t) using Newton's Law of Cooling. Use k as the unknown constant. dH - (к (Н — 50)) dt (b) Solve the differential equation. NOTE: Round constants to 5 decimal places if needed. H(t) -0.062t 34 е + 50 (c) When will the temperature of the juice have dropped to 56°F? NOTE: Round your answer to the nearest minute. After |28 minutes, the temperature will have dropped to 56°F.
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