Question
Asked Aug 4, 2019
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At what rate must the potential difference between the plates of a parallel-plate capacitor with a 2.8 μF capacitance be changed to produce a displacement current of 1.5 A?

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Expert Answer

Step 1

Given

Capacitance C = 2.8 x 10-6 F

Current I = 1.5 A

Step 2

Formula Used

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dQ := I dt Q CV

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Step 3

Solution

...
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do I = dt CdV I dt dV I dt C dV 1.5 2.8x 10 dt dV = 5.36X10V/s dt

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