Question
Asked Feb 7, 2020
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Atmospheric chemistry involves highly reactive, odd-electron molecules such as the hydroperoxyl radical HO2, which decomposes into H2O2 and O2. The following data was obtained at 298 K.
 
Time (μμs) [HO2] (μμM)
0.00 8.50
0.60 5.10
1.00 3.60
1.40 2.60
1.80 1.80
2.40 1.10
 
 
Determine the rate law for the reaction. Do not add multiplication symbols to your answer.

 
Rate=
 
Determine the value of the rate constant at 298 K.
     μs-1 
 
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Expert Answer

Step 1

The balanced equation and the rate of the equation is expressed below:

Chemistry homework question answer, step 1, image 1

Step 2

Order can be determined by plotting time versus concentration and also time versus ln[conc] and it has to be checked which graph is the straight line. If the time versus concentration gives a straight line, then it will be a zero order reaction and if the time versus ln[conc] gives a straight line, then it is a first order reaction. The data is given below:

Chemistry homework question answer, step 2, image 1

Step 3

The graphs of time versus [OH2] is given below:

Chemistry homework question answer, step 3, image 1

...

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