Question
Asked Oct 10, 2019
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A rod of length 70 cm and mass 2.6 kg is suspended by two strings which are 41 cm long, one at each end of the rod. The string on side B is cut. Find the magnitude of the initial acceleration of end B.

The string on side B is retied and now has only half the length of the string on side A. Find the magnitude of the initial acceleration of the end B when the string is cut.

B
L
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B L

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B
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B

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Expert Answer

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Step 1

The bar has only one other force acting on it when string B is cut, and that would be gravity. The gravity always acts at the center of mass, or at a distance 35cm.

Write the expression for torque and equate with the torque due to force of gravity.

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Step 2

Write the expression for linear acceleration, and solve for magnitude of the initial acceleration of end B.

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a= aL (21rad/s)(.70m) 14.7m/s2

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Step 3

The angle made with t...

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'd/2 0 cos L 0.41/2 =cos 0.70 = 72.90

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