Based on your experimental observations from this lab and evidence from previous labs, describe a gold nanoparticle. As part of your description, make a comparison of gold nanoparticles with:Solid precipitates formed by reacting hydroxide salts with iron or copper solutions.Aqueous solutions produced from placing NaCl in water.Aqueous solutions produced from placing sugar in water.Aqueous solutions produced from placing food dye in water.For your comparisons:Describe how nanoparticles are similar and different fromeach system listed (1a‐ 1d).

Question
Asked Nov 21, 2019
286 views

Based on your experimental observations from this lab and evidence from previous labs, describe a gold nanoparticle. As part of your description, make a comparison of gold nanoparticles with:

  1. Solid precipitates formed by reacting hydroxide salts with iron or copper solutions.

  2. Aqueous solutions produced from placing NaCl in water.

  3. Aqueous solutions produced from placing sugar in water.

  4. Aqueous solutions produced from placing food dye in water.

For your comparisons:

  • Describe how nanoparticles are similar and different from

    each system listed (1a‐ 1d).

check_circle

Expert Answer

Step 1

1. Solid precipitates formed by reacting hydroxide salts with iron or copper solutions:

If sodium hydroxide solution is then added, a transition metal hydroxide is formed. Transition metal hydroxides are insoluble, so they form solid precipitates. These precipitates often appear as small particles suspended in a solution. There would be no absorbance value. But there would be light scattering due suspended particles. However, the conductivity would be high since their ions (Na+ & SO4-2) present. Gold nanoparticles have light scattering and an absorbance value very close to 0 and is non-conductive since there are no ions present.

Step 2
  1. Aqueous solutions produced from placing NaCl in water.

 Answer: On the microscopic level the NaCl molecules are added to the H2O and the bonds between Na and Cl dissociate leading to charged Na+ ions and Cl- ions and the water molecules move in between each of them and the negative OH- ion is attracted to the positive Na+ ions and the H+ ions are attracted to the negative Cl ions. There would be no absorbance value and there would be no light scattering either. However, the conductivity would be high since their ions present. Gold nanoparticles have light scattering and an absorbance value very close to 0 and is non-conductive since there are no ions present.

Step 3
  1. Aqueous solutions produced from placing sugar in water.

Answer: On the molecular level the sugar molecules break apart into smaller molecules undergoing dissolution in which the C12H22O11 is broken down into individual molecules that are not charged. Since there were no charged molecules the conductivity of the solution i...

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Chemistry

Related Chemistry Q&A

Find answers to questions asked by student like you
Show more Q&A
add
question_answer

Q: aion ol tne reaction E17B.3(b) The rate constant for the first-order decomposition of a compound A i...

A: The term first order reaction is defined for those reactions which proceed at a rate that has a line...

question_answer

Q: A. What is the mass number of an atom of Iron ( atomic number 26) with 32 neutrons?  B. Is this like...

A: Click to see the answer

question_answer

Q: Draw the structure for the dipeptide Ala-Gly.

A: Dipeptide bond: The two amino acids linked via peptide bond. Peptide bond is formed by the reaction ...

question_answer

Q: Balance the net ionic equation that describes this reaction.  Fe+Pd^2+-->Fe^3++Pd

A: Balance the given equation-Fe+Pd2+→Fe3++Pd

question_answer

Q: Calculate the equilibrium concentrations of the different species in a 0.0100 M solution of sulfurou...

A: Given information:pH of solution = 4.00Concentration of sulfurous acid = 0.0100 M

question_answer

Q: Be sure to answer all parts. Sucrose (CHOn, table sugar) is oxidized in the body by O, via a complex...

A: A balanced chemical equation is an equation which contains same elements in same number on both the ...

question_answer

Q: Octahedral octanedral 2. BrF5 Total Valence Electrons 08 DH M 0.CT alo inn 0e 42 Bromine pentaflnori...

A: The electronic configurations of Bromine and Fluorine are shown below.

question_answer

Q: Like several other bonds, carbon-oxygen bonds have lengths and strengths that depend on the bond ord...

A: A) Lewis structure of HCO3-:

question_answer

Q: Indicate which structures have dipole moments and show their direction for SF4?

A: Dipole moment  in molecules:The following molecules PF3, BrF3, SF4 have dipole moments and the struc...