Question
Asked Feb 13, 2020
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The rate constant of a reaction is 5.8*10-3s-1 at 25 degrees celcius and the activation energy is 33.6 kJ/mole. What is k at 75 degrees celcius? Enter your answer in scientific notation.

Be sure to answer all parts.
The rate constant of a reaction is 5.8 × 10¯³ s at 25°C, and the activation energy is 33.6 kJ/mol. What
is k at 75°C? Enter your answer in scientific notation.
x 10
s1
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Be sure to answer all parts. The rate constant of a reaction is 5.8 × 10¯³ s at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C? Enter your answer in scientific notation. x 10 s1

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Expert Answer

Step 1

Given:

Temperature T1 = 25 oC = 298 K.

Temperature T2 = 75 oC = 348 K.

Activation energy (Ea) = 33.6 KJ/mol.

Rate Constant at T1 (K1) = 5.8×10-3 s-1.

Rate Constant at T2 (K2) = ?

Step 2

Arrhenius equation is given by,

Chemistry homework question answer, step 2, image 1

...

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