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A negatively regulated operon in E. coli, encodes two enyzmes A and B from a single mRNA transcript, which degrade an environmental toxin. The presence of the toxin induces transcription of the operon. You have isolated mutations in both genes (A - and B-) that result in non-functional proteins. You have also isolated a regulatory mutation, which you are calling m1, that that results in constitutive synthesis of both proteins A and B. The corresponding wild-type allele is designated m1+. When you test different genotypes and different partial diploids using F' strains, you obtain the results shown in this table. Which one of the following conclusions is supported by the results? a b с Genotype A+B+ (wild-type) AB+ A+B m1 A*B* m1+A+B/F': m1 AB* m1 A B+/F': m1 A*B- d Protein A produced? no induction no no no yes no yes with induction yes no T yes yes yes yes Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. m1 is a cis-regulatory mutation in an operator sequence. no induction m1 is a cis-regulatory mutation in a gene encoding a repressor to the operon. m1 is a mutation in one of the enzyme-encoding genes. no no no yes yes no Protein B produced? with induction yes yes no m1 is a trans-regulatory mutation in a gene encoding a repressor to the operon. yes yes yes

A negatively regulated operon in E. coli, encodes two enyzmes A and B from a single mRNA transcript, which degrade an environmental toxin. The presence of the toxin induces transcription of the operon. You have isolated mutations in both genes (A - and B-) that result in non-functional proteins. You have also isolated a regulatory mutation, which you are calling m1, that that results in constitutive synthesis of both proteins A and B. The corresponding wild-type allele is designated m1+. When you test different genotypes and different partial diploids using F' strains, you obtain the results shown in this table. Which one of the following conclusions is supported by the results? a b с Genotype A+B+ (wild-type) AB+ A+B m1 A*B* m1+A+B/F': m1 AB* m1 A B+/F': m1 A*B- d Protein A produced? no induction no no no yes no yes with induction yes no T yes yes yes yes Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. m1 is a cis-regulatory mutation in an operator sequence. no induction m1 is a cis-regulatory mutation in a gene encoding a repressor to the operon. m1 is a mutation in one of the enzyme-encoding genes. no no no yes yes no Protein B produced? with induction yes yes no m1 is a trans-regulatory mutation in a gene encoding a repressor to the operon. yes yes yes

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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A negatively regulated operon in E. coli, encodes two enyzmes A and B from a single mRNA transcript, which degrade an environmental toxin. The presence of the toxin induces transcription of the operon. You have isolated mutations in both genes (A - and B-) that result in non-functional proteins. You have also isolated a regulatory mutation, which you are calling m1, that that results in constitutive synthesis of both proteins A and B. The corresponding wild-type allele is designated m1+. When you test different genotypes and different partial diploids using F' strains, you obtain the results shown in this table. Which one of the following conclusions is supported by the results? a b с Genotype A+B+ (wild-type) AB+ A+B m1 A*B* m1+A+B/F': m1 AB* m1 A B+/F': m1 A*B- d Protein A produced? no induction no no no yes no yes with induction yes no T yes yes yes yes Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. m1 is a cis-regulatory mutation in an operator sequence. no induction m1 is a cis-regulatory mutation in a gene encoding a repressor to the operon. m1 is a mutation in one of the enzyme-encoding genes. no no no yes yes no Protein B produced? with induction yes yes no m1 is a trans-regulatory mutation in a gene encoding a repressor to the operon. yes yes yes
Transcribed Image Text:A negatively regulated operon in E. coli, encodes two enyzmes A and B from a single mRNA transcript, which degrade an environmental toxin. The presence of the toxin induces transcription of the operon. You have isolated mutations in both genes (A - and B-) that result in non-functional proteins. You have also isolated a regulatory mutation, which you are calling m1, that that results in constitutive synthesis of both proteins A and B. The corresponding wild-type allele is designated m1+. When you test different genotypes and different partial diploids using F' strains, you obtain the results shown in this table. Which one of the following conclusions is supported by the results? a b с Genotype A+B+ (wild-type) AB+ A+B m1 A*B* m1+A+B/F': m1 AB* m1 A B+/F': m1 A*B- d Protein A produced? no induction no no no yes no yes with induction yes no T yes yes yes yes Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. m1 is a cis-regulatory mutation in an operator sequence. no induction m1 is a cis-regulatory mutation in a gene encoding a repressor to the operon. m1 is a mutation in one of the enzyme-encoding genes. no no no yes yes no Protein B produced? with induction yes yes no m1 is a trans-regulatory mutation in a gene encoding a repressor to the operon. yes yes yes
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