Blackjack, or twenty-one as it is frequently called, is a popular gambling game played in Las Vegas casinos. A player is dealt two cards. Face cards (jacks, queens, and kings) and tens have a point value of 10. Aces have a point value of 1 or 11. A 52-card deck contains 16 cards with a point value of 10 (jacks, queens, kings, and tens) and four aces. (1) What is the probability that both cards dealt are aces or 10-point cards? (2) What is the probability that both of the cards are aces? (3) What is the probability that both of the cards have a point value of 10? (4) A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (5) Parts (1), (2), and (3) to determine the probability that a player is dealt blackjack. (Hint: Part (4) is not a hypergeometric problem. Develop your own logical relationship as to how the hypergeometric probabilities from parts (1), (2), and (3) can be combined to answer this question.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Blackjack, or twenty-one as it is frequently called, is a popular gambling game played in Las Vegas casinos. A player is dealt two cards. Face cards (jacks, queens, and kings) and tens have a point value of 10. Aces have a point value of 1 or 11. A 52-card deck contains 16 cards with a point value of 10 (jacks, queens, kings, and tens) and four aces. (1) What is the probability that both cards dealt are aces or 10-point cards? (2) What is the probability that both of the cards are aces? (3) What is the probability that both of the cards have a point value of 10? (4) A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (5) Parts (1), (2), and (3) to determine the probability that a player is dealt
blackjack. (Hint: Part (4) is not a hypergeometric problem. Develop your own logical relationship as to how the hypergeometric probabilities from parts (1), (2), and (3) can be combined to answer this question.

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