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Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 15. A researcher thinks that a diet high in raw corn starch will have a negative or positive effect on blood glucose levels. A sample of 30 patients who have tried the raw corn starch diet have a mean glucose level of 140. Test the hypothesis that the raw cornstarch had an effect at a significant level of 0.05

Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 15. A researcher thinks that a diet high in raw corn starch will have a negative or positive effect on blood glucose levels. A sample of 30 patients who have tried the raw corn starch diet have a mean glucose level of 140. Test the hypothesis that the raw cornstarch had an effect at a significant level of 0.05

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 15. A

researcher thinks that a diet high in raw corn starch will have a negative or positive effect on

blood glucose levels. A sample of 30 patients who have tried the raw corn starch diet have a

mean glucose level of 140. Test the hypothesis that the raw cornstarch had an effect at a

significant level of 0.05

 

Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 15. A researcher thinks that a diet high in raw corn starch will have a negative or positive effect on blood glucose levels. A sample of 30 patients who have tried the raw corn starch diet have a mean glucose level of 140. Test the hypothesis that the raw cornstarch had an effect at a significant level of 0.05 Step 1: Determine the null hypothesis Ho: µ = H:u + Step 2: Two-tailed test Step 3: Select significance level a = Step 4: Do we do a Z test of T test? Step 5: Find the critical value Zeri from the t Table. Lvel of Confidence Draw and label the graph. From the t Table. Zerit fora = 0.05, ± 1.96 Fail to Reject Reject Reject Note that a= 0.05 (5%) means 2.5% in each tail. This alpha level indicates the Level of Confidence to be 95%. a/2 a/2 Zcrit = Zcrit = Step 6: Calculate the Test Statistic (Zobt) N = X = Step 7-9. State the conclusion
Transcribed Image Text:Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 15. A researcher thinks that a diet high in raw corn starch will have a negative or positive effect on blood glucose levels. A sample of 30 patients who have tried the raw corn starch diet have a mean glucose level of 140. Test the hypothesis that the raw cornstarch had an effect at a significant level of 0.05 Step 1: Determine the null hypothesis Ho: µ = H:u + Step 2: Two-tailed test Step 3: Select significance level a = Step 4: Do we do a Z test of T test? Step 5: Find the critical value Zeri from the t Table. Lvel of Confidence Draw and label the graph. From the t Table. Zerit fora = 0.05, ± 1.96 Fail to Reject Reject Reject Note that a= 0.05 (5%) means 2.5% in each tail. This alpha level indicates the Level of Confidence to be 95%. a/2 a/2 Zcrit = Zcrit = Step 6: Calculate the Test Statistic (Zobt) N = X = Step 7-9. State the conclusion
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