Question
Asked Nov 18, 2019
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Will the exact amount of potassium hydroxide be critical to this reaction and why?

Br
Н.
Н + K-ОН
120°
к-ОН +
Br
Br
Br
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Br Н. Н + K-ОН 120° к-ОН + Br Br Br

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Expert Answer

Step 1

The given reaction is a bimolecular elimination reaction where the bromine is eliminated when OH- attacks the site where bromine is attached from the opposite side.

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Br Br

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Step 2

The molecule goes into the transition phase where OH- is attacking from one side and Br- is leaving from the other side along with the release of H+ which causes the formation of double bond at the end of the step.

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Step 3

A similar attack happens in the second step ...

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к-он +

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Organic reactions

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