Breathalyzers determine the alcohol content in a person's breath by the following (unbalanced) redox reaction: C2H5OH + Cr2O72− → CH3CO2H + Cr3+ (acidic solution) If analysis of a breath sample generates 7.70 x 10-4 M Cr3+ ions in 20.0 mL, how many mg of alcohol did it contain? (This is a case of balancing the chemical equation correctly, using redox reactions. Once you have the correct stoichiometric ratio between ethanol and Cr3+, as well as the molecular weight of the species, it is no further electrochemistry, just a moles-to-grams conversion.)

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