(C) To determine the recombination frequency between these 2 genes, you perform several crosses where you cross an F1 from part (a) with a yellow- bodied, crinkled-wing fly. You get the following results. What is the distance between the genes for body color and wing surface in map units?
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- To determine the recombination frequency between body color and wing genes in flies, you perform several crosses where you cross an F1 having red body and smooth wings with a yellow-bodied, crinkle-winged fly. You get the following results. What is the distance between the genes for body color and wing surface in map units?When true-breeding mice with brown fur and short tails (BBtt)were crossed to true-breeding mice with white fur and long tails(bbTT), all of the F1 offspring had brown fur and long tails. TheF1 offspring were crossed to mice with white fur and short tails.What are the possible phenotypes of the F2 offspring? Which F2offspring are recombinant, and which are nonrecombinant? Whatare the ratios of phenotypes of the F2 offspring if independentassortment is taking place? How are the ratios affected by linkage?In a series of two-point map crosses involving five genes locatedon chromosome II in Drosophila, the following recombinant (single-crossover) frequencies were observed:pr–adp 29pr–vg 13pr–c 21pr–b 6adp–b 35adp–c 8adp–vg 16vg–b 19vg–c 8c–b 27 If the adp gene is present near the end of chromosome II(locus 83), construct a map of these genes.
- The A locus and the D locus are so tightly linked that norecombination is ever observed between them. If Ad/Ad is crossed with aD/aD and the F1 is intercrossed,what phenotypes will be seen in the F2 and in whatproportions?. If you intercrossed F1 heterozygotes of the formA b / a B in mice, the phenotypic ratio among the F2progeny would vary with the map distance betweenthe two genes. Is there a simple way to estimate themap distance based on the frequencies of the F2phenotypes, assuming rates of recombination areequal in males and females? Could you estimatemap distances in the same way if the mouse F1heterozygotes were A B / a b?In a series of two-point map crosses involving five genes locatedon chromosome II in Drosophila, the following recombinant (single- crossover) frequencies were observed:pr–adp 29pr–vg 13pr–c 21pr–b 6adp–b 35adp–c 8adp–vg 16vg–b 19vg–c 8c–b 27 In another set of experiments, a sixth gene (d) was testedagainst b and pr, and the results were d - b = 17% andd - pr = 23%. Predict the results of two-point mapsbetween d and c, d and vg, and d and adp.
- . In a particular kind of ornamental flower, the wildtype flower color is deep purple, and the plants aretrue-breeding. In one true-breeding mutant stock, theflowers have a reduced pigmentation, resulting in alavender color. In a different true-breeding mutantstock, the flowers have no pigmentation and are thuswhite. When a lavender-flowered plant from the firstmutant stock was crossed to a white-flowered plantfrom the second mutant stock, all the F1 plants hadpurple flowers. The F1 plants were then allowed toself-fertilize to produce an F2 generation. The 277 F2plants were 157 purple : 71 white : 49 lavender. a. Explain how flower color is inherited. Is this traitcontrolled by the alleles of a single gene?b. What kinds of progeny would be produced if lavender F2 plants were allowed to self-fertilize?In Figure 5-18c, why is the crossover shown occurring inthe orange segments of DNA?In a series of two-point mapping crosses involving five genes located on chromosome II in Drosophila, the following recombinant (single-crossover) frequencies were observed: pr–adp 29% pr–vg 13 pr–c 21 pr–b 6 adp–b 35 adp–c 8 adp–vg 16 vg–b 19 vg–c 8 c–b 27 (a) Given that the adp gene is near the end of chromosome II (locus 83), construct a map of these genes. (b) In another set of experiments, a sixth gene, d, was tested against b and pr: d–b 17% d–pr 23% Predict the results of two-point mapping between d and c, d and vg, and d and adp.
- Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?In a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data: Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000 Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.b) You test cross an F1 fish (with genotype BbCc) and obtain 1000 offsprings in F2 generation with the following results: 474 Bbcc, 480 bbCc, 20 BbCc and 26 bbcc.1. Create and fill in a Punnet square for this cross.2. What type of cross is it? 3. Are these loci linked? 4. What are the two parental classes and the two recombinant classes of offspring? 5. What is the percentage of recombination between these two loci? Show your calculations. 6. How many map units apart are they?