C.-Y.8253ND 8.5TY+x10-1099 10-2 10 10Y 01OLa4. Formic acid, HFor, has a K value equal to about 1.8 x 104. A student is asked to prepare a buffer havinga pH of 3.90 from a solution of formic acid and a solution of sodium formate having the same molarity.How many milliliters of the NaFor solution should she add to 20. mL of the HFor solution to make thebuffer? (See discussion of buffers.)a 1.ID a04(10)37YCHY J MyZ0) (NaFor )Vr20)аttachnAll5. How many mL of 0.10 M NaOH should the student add to 20 mL 0.10 M HFor if she wished to preparemLa buffer with a pH of 3.90, the same as in Problem 4?mL41

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Asked Nov 12, 2019
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I need assistance with getting to the answer of question 5, please. See attached image. Thank you!

C.
-Y.8
253ND 8.5
TY
+x
10-10
99 10-2 10 10Y 01O
La
4. Formic acid, HFor, has a K value equal to about 1.8 x 104. A student is asked to prepare a buffer having
a pH of 3.90 from a solution of formic acid and a solution of sodium formate having the same molarity.
How many milliliters of the NaFor solution should she add to 20. mL of the HFor solution to make the
buffer? (See discussion of buffers.)a 1.ID a04(10)37Y
CHY J MyZ0) (NaFor )
Vr20)
а
ttachn
All
5. How many mL of 0.10 M NaOH should the student add to 20 mL 0.10 M HFor if she wished to prepare
mL
a buffer with a pH of 3.90, the same as in Problem 4?
mL
41
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C. -Y.8 253ND 8.5 TY +x 10-10 99 10-2 10 10Y 01O La 4. Formic acid, HFor, has a K value equal to about 1.8 x 104. A student is asked to prepare a buffer having a pH of 3.90 from a solution of formic acid and a solution of sodium formate having the same molarity. How many milliliters of the NaFor solution should she add to 20. mL of the HFor solution to make the buffer? (See discussion of buffers.)a 1.ID a04(10)37Y CHY J MyZ0) (NaFor ) Vr20) а ttachn All 5. How many mL of 0.10 M NaOH should the student add to 20 mL 0.10 M HFor if she wished to prepare mL a buffer with a pH of 3.90, the same as in Problem 4? mL 41

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Step 1

Given information,

The concentration of NaOH is 0.10 M.

Volume of formic acid is 20 mL.

The concentration of formic acid is 0.10 M.

Use Hen...

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pH pK, +log ([Conjugate base][Acid) 3.90 3.74 +log ([Conjugate ba se]/[Acid]) [Conjugate base]/[Acid-1.45 [Conjugate base] 1.45x[Acid]

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