Question
Asked Dec 21, 2019
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The circuit in Figure P18.62 contains two resistors, R1 = 2.0
kΩ and R2 = 3.0 kΩ, and two capacitors, C1 = 2.0 µF and C2 =
3.0 µF, connected to a battery with emf ε = 120 V. If there are
no charges on the capacitors before switch S is closed, determine
the charges q1 and q2 on capacitors C1 and C2, respectively,
as functions of time, after the switch is closed. Hint: First
reconstruct the circuit so that it becomes a simple RC circuit
containing a single resistor and single capacitor in series, connected
to the battery, and then determine the total charge q
stored in the circuit.

C1
R1
R2
C2
Figure P18.62
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C1 R1 R2 C2 Figure P18.62

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Expert Answer

Step 1

The resisters (R1 and R2) are connected in parallel. Thus, the equivalent resistance (R) of the resistors can be calculated as,

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R,R, R = R +R, (2.0ΚΩ) (3.0 κ) (2.0 k2) +(3.0 k2) -1.2 kΩ

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Step 2

The capacitors (C1 and C2) are connected in parallel. Thus, the equivalent capacitance (C) of the capacitors can be calculated as,

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C=C,+C, = (2.0 µF) + (3.0 µF) = 5.0 µF

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Step 3

For charging circuit, the time con...

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T = RC = (1.2 k2)(5.0 µF) =(1.2x10' 2)(5.0×10“ F) = 6.0x10 s

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Electric Charges and Fields

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