Calculate ΔH° for the process Sb(s) + 52Cl2(g) ⟶ SbCl5(s)

from the following information:

Sb(s) + 32Cl2(g) ⟶ SbCl3(s) ΔH° = −314 kJ

SbCl3(s) + Cl2(g) ⟶ SbCl5(s) ΔH° = −80 kJ

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