Question
Asked Oct 7, 2019
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Calculate how many moles of NO2 form when each quantity of reactant completely reacts via the following reaction: 2N2O5(g)→4NO2(g)+ O2(g)

2.7 mol N2O5

7.4 mol N2O5

15.4 g N2O5

2.61 kg N2O5

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Expert Answer

Step 1

Number of moles of NO2 form is to be calculated when each quantity of reactant completely reacts via the given reaction:

a) 2.7 mol N2O5

b) 7.4 mol N2O5

c) 15.4 g N2O5

d) 2.61 kg N2O5

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2N,0, (g)4NO, (g)+ O, (g)

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Step 2

Part a) 2.7 mol N2O5

As per the balanced equation, 2 moles of N2O5 forms 4 moles of NO2 and 1 mole of O2.

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Moles of NO2 formed by 2 moles of N,05 = 4 moles :. Moles of NO, formed by 2.7 moles of N,O, = 2.7 moles of N205 =5,4 moles NO2 2 moles of N,0 4 moles NO X Thus, 2.7 moles of N,O; forms 5.4 moles of NO2.

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Step 3

Part b) 7.4 mol N2O5

As per the balanced equation, 2 moles of N2O5 forms 4 moles of NO2 and 1 mole of O2.

...
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Moles of NO2 formed by 2 moles of N,O :. Moles of NO, formed by 7.4 moles of N,O 4 moles 7.4 moles of N0s =14.8 moles NO, 4 moles NO X 2 moles of N,O Thus, 7.4 moles ofN,O, forms 14.8 moles of NO,

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