Calculate new per unit reactance of T2. Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u. Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u. %3D Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u. T;: 25 MVA, 13.2 - 161 kV, X = 0.1 p.u. %3D T;: 15 MVA, 13.8 –. 161 kV, X = 0.1 p.u. %3D Line: j100 N (actual) Select a base of 100 MVA and 161 kV in the transmission line. T (M) Line (M2) O 0.67 pu 6.67 pu O 0.33 pu O.015 pu

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter9: Unsymmetrical Faults
Section: Chapter Questions
Problem 9.2P
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Calculate new per unit reactance of T2.
Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u.
%3D
Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u.
%3D
Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u.
T: 25 MVA, 13.2 - 161 kV, X %3D 0.1 р.u.
T;: 15 MVA, 13.8 –. 161 kV, X = 0.1 p.u.
Line: j100 N (actual)
Select a base of 100 MVA and 161 kV in the transmission line.
M)
T
G
Line
(M2)
0.67 pu
O 6.67 pu
О 0.33 pu
0.015 pu
cede
Transcribed Image Text:Calculate new per unit reactance of T2. Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u. %3D Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u. %3D Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u. T: 25 MVA, 13.2 - 161 kV, X %3D 0.1 р.u. T;: 15 MVA, 13.8 –. 161 kV, X = 0.1 p.u. Line: j100 N (actual) Select a base of 100 MVA and 161 kV in the transmission line. M) T G Line (M2) 0.67 pu O 6.67 pu О 0.33 pu 0.015 pu cede
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