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Calculate the ΔG°rxn using the following information. 4 HNO3(g) + 5 N2H4(l) → 7 N2(g) + 12 H2O(l) ΔG°rxn = ? ΔH°f (kJ/mol) HNO3 = -133.9 N2H4 = 50.6 N2 = 0.0 H2O = -285.8 S°(J/mol∙K) HNO3 = 266.9 N2H4 = 121.2 N2 = 191.6 H2O = 70.0

Calculate the ΔG°rxn using the following information. 4 HNO3(g) + 5 N2H4(l) → 7 N2(g) + 12 H2O(l) ΔG°rxn = ? ΔH°f (kJ/mol) HNO3 = -133.9 N2H4 = 50.6 N2 = 0.0 H2O = -285.8 S°(J/mol∙K) HNO3 = 266.9 N2H4 = 121.2 N2 = 191.6 H2O = 70.0

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.73QP
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Calculate the ΔG°rxn using the following information.

4 HNO3(g) + 5 N2H4(l) → 7 N2(g) + 12 H2O(l) ΔG°rxn = ?
ΔH°f (kJ/mol)
HNO3 = -133.9
N2H4 = 50.6
N2 = 0.0
H2O = -285.8

S°(J/mol∙K)
HNO3 = 266.9
N2H4 = 121.2
N2 = 191.6
H2O = 70.0

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