Asked Oct 29, 2019

Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 343oC is 9.39 × 1023 m-3. The density and atomic weight (at 343°C) for this metal are 7.75 g/cm3 and 142.6 g/mol, respectively.


Expert Answer

Step 1


Temperature of metal= 343°C= (343+273)K=616K

Density of the metal= 7.75g/cc=7.75x106g/m3

Atomic mass = 142.6g/mol

Vacancies = 9.39x 1023/m3

Step 2

The number of atomic sites


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A atomic weight 7.75x100x6.022 x 1025 142.6 =3.273x1028atom/m3

Step 3

The formula for the energy of formation of v...


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no of vaccancies no of atomic sites E -KT xIn where K 8.62x10 9.39 x 1023 E-(8.62x10(616K ) In| 3.273x 1023 =10.4593eV/atom


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