calculate the equilibrium constant for the reaction:Hg2+(aq) + 2Ag(s) -------> Hg(l) + 2Ag+(aq)Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: ___________G° for this reaction would be _________greaterless   than zero.  Hg2+(aq) + 2 e- ----->  Hg(l)0.855Ag+(aq) + e- ------> Ag(s)0.799

Asked Apr 27, 2019

calculate the equilibrium constant for the reaction:

Hg2+(aq) + 2Ag(s) -------> Hg(l) + 2Ag+(aq)

Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. 

Equilibrium constant: ___________

G° for this reaction would be _________greaterless   than zero.



Hg2+(aq) + 2 e- ----->  Hg(l) 0.855
Ag+(aq) + e- ------> Ag(s) 0.799
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Step 1

The EMF of the cell is calculated by below,

Step 2

Oxidation takes place in anode and reduction take place in cathode so EMF of the cell is,

Step 3

According to the Nernst equation, if cell reaction is...


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