Calculate the equilibrium constant of oxidation reaction (3) at 675, 875 and 1075 K and fromVan’t Hoff equation calculate the heat of reaction by using the graphical method. AGAG vs T4G675-355100Reaction 1875-320700200400G0080010001200500001075-286300-100000-150000675-394667Reaction 2875-394835-2000001075-395003-250000-300000675-170863.75350000Reaction 3875-188393.754000001075-205923.75450000 For below given chemical reactions:(1) 2Ni(s) + 02(9) = 2N10(s)AG; = -471200 + 172T (J/mol)(2) C(s) + 02(9) = CO2(9)AG² = -394100 – 0.84T (J/mol)%3D(3) C(s) + /½ 0zc0) = CO9)AG; = -111700 - 87.65T (J/mol)

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Answered: Calculate the equilibrium constant of…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Calculate the equilibrium constant of oxidation reaction (3) at 675, 875 and 1075 K and from
Van’t Hoff equation calculate the heat of reaction by using the graphical method.

AG
AG vs T
4G
675
-355100
Reaction 1
875
-320700
200
400
G00
800
1000
1200
50000
1075
-286300
-100000
-150000
675
-394667
Reaction 2
875
-394835
-200000
1075
-395003
-250000
-300000
675
-170863.75
350000
Reaction 3
875
-188393.75
400000
1075
-205923.75
450000

For below given chemical reactions:
(1) 2Ni(s) + 02(9) = 2N10(s)
AG; = -471200 + 172T (J/mol)
(2) C(s) + 02(9) = CO2(9)
AG² = -394100 – 0.84T (J/mol)
%3D
(3) C(s) + /½ 0zc0) = CO9)
AG; = -111700 - 87.65T (J/mol)

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