Question
Asked Jan 29, 2020
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Calculate the molalities of the following aqueous solutions:
 
(a) 1.000 M sugar (C12H22O11) solution (density of solution = 1.095 g/mL)
 

 
(b) 1.05 M NaOH solution (density of solution 1.082 g/mL)
 

 
(c) 3.08 M NaHCO3 solution (density of solution 1.077 g/mL)
 

 

 

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Expert Answer

Step 1

The molality of a solution is calculated using the below formula.

Chemistry homework question answer, step 1, image 1
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Step 2

(a)

Determination of mass of solute:

1.00 M C12H22O11means 1.00 mol/L.  That is, 1000 mL of sugar solution has 1.00 moles.

Thus, the moles of solute = 1.00 mol.

The molar mass of C12H22O11 is 342.3 g/mol

The Mass of solute (C12H22O11) present is calculated as,

Chemistry homework question answer, step 2, image 1
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Step 3

Determination of mass of solution and mass of solvent:

The density of solution is...

Chemistry homework question answer, step 3, image 1
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