# Calculate the molalities of the following aqueous solutions: (a) 1.000 M sugar (C12H22O11) solution (density of solution = 1.095 g/mL)  (b) 1.05 M NaOH solution (density of solution 1.082 g/mL)  (c) 3.08 M NaHCO3 solution (density of solution 1.077 g/mL)

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Calculate the molalities of the following aqueous solutions:

(a) 1.000 M sugar (C12H22O11) solution (density of solution = 1.095 g/mL)

(b) 1.05 M NaOH solution (density of solution 1.082 g/mL)

(c) 3.08 M NaHCO3 solution (density of solution 1.077 g/mL)

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Step 1

The molality of a solution is calculated using the below formula.

Step 2

(a)

Determination of mass of solute:

1.00 M C12H22O11means 1.00 mol/L.  That is, 1000 mL of sugar solution has 1.00 moles.

Thus, the moles of solute = 1.00 mol.

The molar mass of C12H22O11 is 342.3 g/mol

The Mass of solute (C12H22O11) present is calculated as,

Step 3

Determination of mass of solution and mass of solvent:

The density of solution is...

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